Combinatorics and Graph Theory

   

Number of Non—Zero Coefficients of (1 + X^a + X^b)^n Over F_p

Authors: Andy Zhuang

The paper studies explicit formulas for (N_p(n;a,b)), the count of coefficients that remain non--zero modulo a prime (p) in the trinomial power ((1+x^{a}+x^{b})^{n}) with (0<a<b<p). Leveraging Lucas’ digit—wise criterion and the matrix--automaton framework of Amdeberhan--Stanley, we first prove a emph{carryu2011free theorem}: if every baseu2011(p) digit of (n) does not exceed (bigllfloor (p-1)/b bigrfloor) and the generated $x$-exponents do not overlap at every digit position, then no crossu2011digit carries occur and the exponents are unique for each digit position. This leads to (N_p(n;a,b)) being factorized as (prod_{l}binom{n_l+2}{2}), where $n_l$ are digits of $n$ under base-$p$.The paper next derives a upper bound (N_p(n;a,b)le 3^{,w_p(n)}), where (w_p(n)) is the sum of the baseu2011(p) digits of (n), and shows that equality holds precisely when every digit of (n) is (0) or (1). Worked examples—including the case ((1+x+x^{3})^{n}) over (mathbb{F}_7)—demonstrate the formulas in practice, and the discussion shows our contributions within earlier studies on automatic sequences and multinomial Lucas theorems.

Comments: 8 Pages.

Download: PDF

Submission history

[v1] 2025-08-19 23:24:31

Unique-IP document downloads: 227 times

Vixra.org is a pre-print repository rather than a journal. Articles hosted may not yet have been verified by peer-review and should be treated as preliminary. In particular, anything that appears to include financial or legal advice or proposed medical treatments should be treated with due caution. Vixra.org will not be responsible for any consequences of actions that result from any form of use of any documents on this website.

Add your own feedback and questions here:
You are equally welcome to be positive or negative about any paper but please be polite. If you are being critical you must mention at least one specific error, otherwise your comment will be deleted as unhelpful.

comments powered by Disqus