With the Pythagorean Triples C^2 = A^2 + B^2 We Obtain that C^2 * N = A^2 * N + B^2 * N and C^2 * N is a Power of C with Exponent> 2

Giovanni Di Savino

With the Pythagorean Triples C^2 = A^2 + B^2 We Obtain that C^2 * N = A^2 * N + B^2 * N and C^2 * N is a Power of C with Exponent> 2

It is possible to multiply the three powers by the same value square of a Pythagorean triple and obtain that the sum of two is equal to the power of the third.

Comments: 4 Pages.

Download: PDF

Submission history

[v1] 2022-08-07 22:47:44

Unique-IP document downloads: 196 times

Vixra.org is a pre-print repository rather than a journal. Articles hosted may not yet have been verified by peer-review and should be treated as preliminary. In particular, anything that appears to include financial or legal advice or proposed medical treatments should be treated with due caution. Vixra.org will not be responsible for any consequences of actions that result from any form of use of any documents on this website.

Add your own feedback and questions here:
You are equally welcome to be positive or negative about any paper but please be polite. If you are being critical you must mention at least one specific error, otherwise your comment will be deleted as unhelpful.

Number Theory

With the Pythagorean Triples C^2 = A^2 + B^2 We Obtain that C^2 * N = A^2 * N + B^2 * N and C^2 * N is a Power of C with Exponent> 2

Submission history