There is no a nucleus with more than two neighboring protons, because the presence of a third proton creates an increased negative potential that exceeds their stability potential, causing a cleaving (beta decay β+) of this third proton. These two protons are next to each other and due to their opposite magnetic moments they create a column of magnetic field, while a magnetic column is created by the rotated neutrons as well. So, the first phase of the nuclei structure ends in He-4. Of course, protons are immobile, while neutrons are rotating around them. However, how is the second nucleus He-4 added? Apparently having a common axis with the first He-4. But why is beryllium Be-8, with the two superimposed nuclei He-4, unstable? We will prove that column construction is based on the stability of carbon C-12 and oxygen O-16, which consist of three superimposed nuclei He-4 and four He-4 respectively. Consequently, the structure of the nuclei begins with the so-called lower-order nuclei, as the deuterium, tritium and helium He-3, which evolve into helium He-4 and then first upper-order oxygen nucleus, that has four helium nuclei He-4 in a column of strong negative electric field.