Authors: Zhang Tianshu
We first get rid of three kinds from A+B=C according to their respective odevity and gcf (A, B, C) =1. Next expound relations between C and paf (ABC) by the symmetric law of odd numbers. Finally we have proven C ≤ Cε [paf (ABC)] 1+ ε such being the case A+B=C, and gcf (A, B, C) =1.
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[v1] 2014-10-19 06:16:32
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